Tuesday, October 03, 2006
JSH: Doodling with quadratics
Consider
x^2 - 5x + 2 = 0
and
y^2 - 7y + 2 = 0
and solve each where I'll not use +/- and just use plusses:
x = (5 + sqrt(21))/2 and y = (7 + sqrt(45))/2.
I can subtract
x^2 - 5x + 2 = 0
from
y^2 - 7y + 2 = 0
to get
y^2 - x^2 = 7y - 5x
and group a bit, and divide by y - x to get
y + x = 2y/(y-x) + 5
so
(7 + sqrt(45))/2 + (5 + sqrt(21))/2 = 2(5 + sqrt(21))/(2 + sqrt(45) - sqrt(21)) + 5
which proves that 2 + sqrt(45) - sqrt(21) must be a factor of 2.
Just doodling.
Just curious, what is the polynomial with integer coefficients that has that as a root?
x^2 - 5x + 2 = 0
and
y^2 - 7y + 2 = 0
and solve each where I'll not use +/- and just use plusses:
x = (5 + sqrt(21))/2 and y = (7 + sqrt(45))/2.
I can subtract
x^2 - 5x + 2 = 0
from
y^2 - 7y + 2 = 0
to get
y^2 - x^2 = 7y - 5x
and group a bit, and divide by y - x to get
y + x = 2y/(y-x) + 5
so
(7 + sqrt(45))/2 + (5 + sqrt(21))/2 = 2(5 + sqrt(21))/(2 + sqrt(45) - sqrt(21)) + 5
which proves that 2 + sqrt(45) - sqrt(21) must be a factor of 2.
Just doodling.
Just curious, what is the polynomial with integer coefficients that has that as a root?