Sunday, August 25, 1996
Minor correction and maybe why this is new, Re: FLT
As usual, almost immediately after that latest post I realized an error. I stated that (z-x) has an nth root. That's true unless it is divisible by n, then it has an (n-1)th root for n and an nth root for other factors, that is, (z-x) = n^n-1 f^n
That means that what I gave isn't a proof for n=3 but that doesn't bother me because it is correct for any othe odd prime. That's because in those cases it is an nth root.
That's probably why I didn't notice it before and why it wouldn't have been noticed until now. I had to make a mistake to get it because if I had remembered that, I would have given up again (and berated myself mercilessly).
That means that what I gave isn't a proof for n=3 but that doesn't bother me because it is correct for any othe odd prime. That's because in those cases it is an nth root.
That's probably why I didn't notice it before and why it wouldn't have been noticed until now. I had to make a mistake to get it because if I had remembered that, I would have given up again (and berated myself mercilessly).
# posted by James Harris @ 12:17 
